For delete the last node in CSLL ,we need some extra effort to complete this task :
- First we need some temporary variables to traverse the all node and reach at last node.
- At last node we have to perform deletion operation.
Working Process
Code Implementation
#include <stdio.h>
#include<math.h>
#include<stdlib.h>
#include<iostream>
#include<conio.h>
struct CreateNode // Node Structure Initialization
{
int data; // for data element
struct CreateNode* nextNode; //for storing the address of next element
};
struct CreateNode *HeadPointer = NULL; // Initialization of HeadPointer
void deleteNodeAtEndInCSLL() // Method of End Deletion
{
struct CreateNode* TempNode1 = NULL; // Create one TempNode
struct CreateNode* TempNode2 = NULL;
TempNode1 = HeadPointer;
while (TempNode1->nextNode != HeadPointer)
{
TempNode2 = TempNode1;
TempNode1 = TempNode1->nextNode;
}
TempNode2->nextNode = HeadPointer;
printf("%d is deleted from the End\n ", TempNode1->data);
}
int main()
{
int choice = 0;
//Create 4 node statically and Initialize manually
struct CreateNode* Node1 = (struct CreateNode *)malloc(sizeof(struct CreateNode *));
struct CreateNode* Node2 = (struct CreateNode *)malloc(sizeof(struct CreateNode *));
struct CreateNode* Node3 = (struct CreateNode *)malloc(sizeof(struct CreateNode *));
struct CreateNode* Node4 = (struct CreateNode *)malloc(sizeof(struct CreateNode *));
struct CreateNode* Node5 = (struct CreateNode *)malloc(sizeof(struct CreateNode *));
Node1->data = 90;
Node2->data = 100;
Node3->data = 200;
Node4->data = 300;
Node5->data = 400;
Node1->nextNode = Node2;
Node2->nextNode = Node3;
Node3->nextNode = Node4;
Node4->nextNode = Node5;
Node5->nextNode = Node1;
HeadPointer = Node1; // HeadPointer pointing to the Node1
printf("Node data before deletion process :\n");
struct CreateNode* Temp = HeadPointer;
while (Temp->nextNode != HeadPointer)
{
printf("%d ", Temp->data);
Temp = Temp->nextNode;
}
printf("%d ", Temp->data);
while (choice == 0)
{
printf("\nPress 0 for End deletion :");
std::cin >> choice;
if (choice == 0)
{
deleteNodeAtEndInCSLL();
}
else
{
choice = 1;
}
}
printf("Node data after deletion process :\n");
Temp = HeadPointer;
while (Temp->nextNode != HeadPointer)
{
printf("%d ", Temp->data);
Temp = Temp->nextNode;
}
printf("%d ", Temp->data);
_getch();
return 0;
}
Time & Space Complexity
- Time Complexity will be O(n) always.
- Space Complexity will be O(1).